Page 2 of 2 FirstFirst 12
Results 11 to 19 of 19

Thread: resistor value

  1. #11
    Join Date
    Sep 2016
    Location
    VN
    Posts
    178
    Thanks Thanks Given 
    17
    Thanks Thanks Received 
    4
    Thanked in
    4 Posts

    Default

    ~0,07ohm (black-violet-silver-gold)
    sound pretty good because stock cx500 use 2 resistor connect in parallel

  2. #12
    Join Date
    Oct 2017
    Location
    Grand Junction, CO
    Posts
    1,828
    Thanks Thanks Given 
    93
    Thanks Thanks Received 
    31
    Thanked in
    29 Posts

    Default

    How many watts can your resistor handle?
    Last edited by ashiekh; 04-03-2019 at 06:08 PM.

  3. #13
    Join Date
    Jul 2007
    Location
    Sweden
    Posts
    348
    Thanks Thanks Given 
    14
    Thanks Thanks Received 
    3
    Thanked in
    3 Posts

    Default

    The black band is not part of the color code, it is just there to tell you which side is the end.
    This is why it's also printed at the very end of the resistor...
    So I would say 0.14ohm 2%

    As further evidence I desoldered a similar resistor in a CX400 just now:
    red - red - silver - gold - (black)
    It reads as ca 0.22ohm on a meter and that is what the resistor color code decodes as too...
    "The one who says it cannot be done should never interrupt the one who is doing it."

  4. The Following User Says Thank You to Per Hansson For This Useful Post:

    asf14tomcat (04-03-2019)

  5. #14
    Join Date
    Oct 2017
    Location
    Grand Junction, CO
    Posts
    1,828
    Thanks Thanks Given 
    93
    Thanks Thanks Received 
    31
    Thanked in
    29 Posts

    Default

    And here was me thinking they increased the gap to the last band to signify which end is which.

    A CX400 pulls say 4 amps, so the 0.22 Ohm resistor will be dissipating 3W; that is quite a bit of wastage (almost one percent).
    Attached Images Attached Images
    Last edited by ashiekh; 04-03-2019 at 06:01 PM.

  6. #15
    Join Date
    Sep 2016
    Location
    VN
    Posts
    178
    Thanks Thanks Given 
    17
    Thanks Thanks Received 
    4
    Thanked in
    4 Posts

    Default

    how about this ? 0,05ohms right?

  7. #16
    Join Date
    Nov 2010
    Location
    Serbia
    Posts
    2,245
    Thanks Thanks Given 
    127
    Thanks Thanks Received 
    10
    Thanked in
    6 Posts

    Default

    Yep, that one should definitely be 0.05 Ω 5%
    Careful what you wish for... You just might get it.

  8. #17
    Join Date
    Oct 2017
    Location
    Grand Junction, CO
    Posts
    1,828
    Thanks Thanks Given 
    93
    Thanks Thanks Received 
    31
    Thanked in
    29 Posts

    Default

    Quote Originally Posted by asf14tomcat View Post
    i think a few mili volt . not measure yet. research datasheet of cm6800 series . in the schematic it look like R18

    R18 connects to ground...

  9. #18
    Join Date
    Sep 2016
    Location
    VN
    Posts
    178
    Thanks Thanks Given 
    17
    Thanks Thanks Received 
    4
    Thanked in
    4 Posts

    Default

    Ground in here is negative (-) in the primary side. Look at negative pin of bridge diode

  10. #19
    Join Date
    Oct 2017
    Location
    Grand Junction, CO
    Posts
    1,828
    Thanks Thanks Given 
    93
    Thanks Thanks Received 
    31
    Thanked in
    29 Posts

    Default

    Now I'm all confused; how does the main current (and so the initial surge) go through R18?

    And there are all sorts of resistors in series

    R10, 11, 64

    R12, 13

    R14, 15

    R16A, 17A

    and I can't see a reason for it (they are not forming a voltage divider, nor is one variable)

    Some components have values, others not.
    Last edited by ashiekh; 04-05-2019 at 07:58 AM.

Posting Permissions

  • You may not post new threads
  • You may not post replies
  • You may not post attachments
  • You may not edit your posts
  •